Material Variances knowing standards and actuals for the same output using a single material
Problem 1
In manufacturing a product GERBER, the standard quantity of material was fixed at 10 kg and the standard price was 200 per kg. The actual quantity consumed was 12 kg and the actual price was 190 per kg. Calculate all possible Material variances.
| 1 | |
|---|---|
| MYV/MSUV MMV | − 400 0 |
| MQV/MUV MPV | − 400 + 120 |
| MCV | − 280 |
Working Notes
The following data could be picked up from the problem
| Standard | Actual | |||
|---|---|---|---|---|
| SQ | SP | AQ | AP | |
| Material 1 | 10 | 200 | 12 | 190 |
| Output | 1 | 1 | ||
units : _Q in kgs, _P in value/kg and _O in units
Assumptions:
- The standards and actuals given are for the same output, assumed to be 1 unit here.
Working Table
| Standard | Actual | |||||||||
|---|---|---|---|---|---|---|---|---|---|---|
| for SO | for AO | for AI | ||||||||
| SQ | SP | SQ(AO) | SC(AO) | SQ(AI) | SC(AI) | AQ | AP | AC | SC(AQ) | |
| Factor | 1 | 1.2 | ||||||||
| Material 1 | 10 | 200 | 10 | 2,000 | 12 | 2,400 | 12 | 190 | 2,280 | 2,400 |
| Total | 10 | 10 | 2,000 | 12 | 2,400 | 12 | 2,280 | 2,400 | ||
| Output | 1 SO | 1 SO(AO) | 1.2 SO(AI) | 1 AO | ||||||
Output (_O) is in units, Quantities (_Q) and Losses (_L) are in kgs, Prices (_P) are in monetary value per kg and Costs (_C) are in monetary values.
Standard Output
| SO | = | 1 unit (given) |
Actual Output
| AO | = | 1 unit (given) |
| (AO) | = |
| ||
| = |
| |||
| = | 1 |
| (AI) | = |
| ||
| = |
| |||
| = |
| |||
| = | 1.2 |
| 1. | SQ(AO) | = | SQ ×
| ||
| = | SQ × 1 |
2. SC(AO) = SQ(AO) × SP
3. SO(AO) = AO
| 4. | SQ(AI) | = | SQ ×
| ||
| = | SQ × 1.2 |
5. SC(AI) = SQ(AI) × SP
| 6. | SO(AI) | = | SO ×
|
7. SC(AQ) = AQ × SP
Solution
Material Cost Variance
MCV = SC(AO) − AC
| = | 2,000 − 2,280 | = | − 280 [Adv] |
Material Price Variance
MPV = SC(AQ) − AC
| = | 2,400 − 2,280 | = | + 120 [Fav] |
Material Quantity/Usage Variance
MQV/MUV = SC(AO) − SC(AQ)
| = | 2,000 − 2,400 | = | − 400 [Adv] |
Material Mix Variance
MMV = SC(AI) − SC(AQ)
| = | 2,400 − 2,400 | = | 0 |
Material Yield/Sub-Usage Variance
MYV/MSUV = SC(AO) − SC(AI)
| = | 2,000 − 2,400 | = | − 400 [Adv] |
Solution (alternative presentation)
| Material 1 | |
|---|---|
| MYV/MSUV SC(AO) 2,000 − − SC(AI) 2,400 SC(AI) 2,400 − − SC(AQ) 2,400 | − 400 0 |
| MQV/MUV SC(AO) 2,000 − − SC(AQ) 2,400 SC(AQ) 2,400 − − AC 2,280 | − 400 + 120 |
| MCV SC(AO) 2,000 − − AC 2,280 | − 280 |
Verification
Verification
| Formula | Material 1 | |
|---|---|---|
| MYV/MSUV + MMV | SC(AO) − SC(AI) SC(AI) − SC(AQ) | − 400 0 |
| MQV/MUV + MPV | SC(AO) − SC(AQ) SC(AQ) − AC | − 400 + 120 |
| MCV | SC(AO) − AC | − 280 |
Simplest
One may use this as the simplest presentation of calculations, since all the amounts used in the formula are present in the working table.If it is for verification purposes, we may avoid the formula column.
Please adopt a presentation based on the examination you are attending, the proportion of marks allotted and time available to/for the problem.
