Material Variances - Single Material - Same Standard Actual output
Practice Problem 2
The standard cost card of a manufacturer shows the following details relating to the materials:
Standard Price = 2 per unit
Standard quantity = 4,000 units
Actual price = 2.50 per unit.
Actual usage of materials = 4,100 units.
Calculate Material Variances.
| 1 | |
|---|---|
| MYV/MSUV MMV | − 200 0 |
| MQV/MUV MPV | − 200 − 2,050 |
| MCV | − 2,250 |
Working Notes
The following data could be picked up from the problem
| Standard | Actual | |||
|---|---|---|---|---|
| SQ | SP | AQ | AP | |
| Material 1 | 4,000 | 2 | 4,100 | 2.50 |
| Output | 1 | 1 | ||
units : _Q in kgs, _P in value/kgs and _O in units
Assumptions:
- The standards and actuals given are for the same output, assumed to be 1 unit here.
Working Table
| Standard | Actual | |||||||||
|---|---|---|---|---|---|---|---|---|---|---|
| for SO | for AO | for AI | ||||||||
| SQ | SP | SQ(AO) | SC(AO) | SQ(AI) | SC(AI) | AQ | AP | AC | SC(AQ) | |
| Factor | 1 | 1.025 | ||||||||
| Material 1 | 4,000 | 2 | 4,000 | 8,000 | 4,100 | 8,200 | 4,100 | 2.5 | 10,250 | 8,200 |
| Total | 4,000 | 4,000 | 8,000 | 4,100 | 8,200 | 4,100 | 10,250 | 8,200 | ||
| Output | 1 SO | 1 SO(AO) | 1.03 SO(AI) | 1 AO | ||||||
Output (_O) is in nos, Quantities (_Q) and Losses (_L) are in units, Prices (_P) are in monetary value per unit and Costs (_C) are in monetary values.
Standard Output
| SO | = | 1 no (given) |
Actual Output
| AO | = | 1 no (given) |
| (AO) | = |
| ||
| = |
| |||
| = | 1 |
| (AI) | = |
| ||
| = |
| |||
| = |
| |||
| = | 1.025 |
| 1. | SQ(AO) | = | SQ ×
| ||
| = | SQ × 1 |
2. SC(AO) = SQ(AO) × SP
3. SO(AO) = AO
| 4. | SQ(AI) | = | SQ ×
| ||
| = | SQ × 1.025 |
5. SC(AI) = SQ(AI) × SP
| 6. | SO(AI) | = | SO ×
|
7. SC(AQ) = AQ × SP
Solution
Material Cost Variance
MCV = SC(AO) − AC
| = | 8,000 − 10,250 | = | − 2,250 [Adv] |
Material Price Variance
MPV = SC(AQ) − AC
| = | 8,200 − 10,250 | = | − 2,050 [Adv] |
Material Quantity/Usage Variance
MQV/MUV = SC(AO) − SC(AQ)
| = | 8,000 − 8,200 | = | − 200 [Adv] |
Material Mix Variance
MMV = SC(AI) − SC(AQ)
| = | 8,200 − 8,200 | = | 0 |
Material Yield/Sub-Usage Variance
MYV/MSUV = SC(AO) − SC(AI)
| = | 8,000 − 8,200 | = | − 200 [Adv] |
Solution (alternative presentation)
| Material 1 | |
|---|---|
| MYV/MSUV SC(AO) 8,000 − − SC(AI) 8,200 SC(AI) 8,200 − − SC(AQ) 8,200 | − 200 0 |
| MQV/MUV SC(AO) 8,000 − − SC(AQ) 8,200 SC(AQ) 8,200 − − AC 10,250 | − 200 − 2,050 |
| MCV SC(AO) 8,000 − − AC 10,250 | − 2,250 |
Verification
Verification
| Formula | Material 1 | |
|---|---|---|
| MYV/MSUV + MMV | SC(AO) − SC(AI) SC(AI) − SC(AQ) | − 200 0 |
| MQV/MUV + MPV | SC(AO) − SC(AQ) SC(AQ) − AC | − 200 − 2,050 |
| MCV | SC(AO) − AC | − 2,250 |
Simplest
One may use this as the simplest presentation of calculations, since all the amounts used in the formula are present in the working table.If it is for verification purposes, we may avoid the formula column.
Please adopt a presentation based on the examination you are attending, the proportion of marks allotted and time available to/for the problem.
